Oracle數據庫如何查找(zhǎo)刪除重複的SQL語句
查詢及刪除重(chóng)複記錄(lù)的SQL語句
1、查找表中多餘的重複記錄(lù),重(chóng)複記錄是根據單個字段(peopleId)來判斷
select * from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
2、刪除表中多餘的重複記錄,重複記錄是根據單個字段(peopleId)來(lái)判斷,隻留(liú)有 rowid最小的記錄
delete from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)
注:rowid為oracle自(zì)帶不用該.....
3、查找表中多(duō)餘的重複記錄(多個字段)
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
4、刪除表(biǎo)中多餘的重複記錄(多個字段),隻(zhī)留(liú)有rowid最小的記(jì)錄
delete from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
5、查找表(biǎo)中多餘的重複記錄(多個字段),不包含rowid最小的記錄
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
(二)
比方說
在A表(biǎo)中存在一個(gè)字段“name”,
而且不(bú)同記錄之間的“name”值(zhí)有可能會相同,
現在就是需(xū)要查詢出在該表中的各記錄之間,“name”值存(cún)在重複的項;
Select Name,Count(*) From A Group By Name Having Count(*) > 1
如果還查性別也相同大則(zé)如下:
Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1
(三)
方法一
declare @max integer,@id integer
declare cur_rows cursor local for select 主字段,count(*) from 表(biǎo)名 group by 主(zhǔ)字段 having count(*) >; 1
open cur_rows
fetch cur_rows into @id,@max
while @@fetch_status=0
begin
select @max = @max -1
set rowcount @max
delete from 表名 where 主字段 = @id
fetch cur_rows into @id,@max
end
close cur_rows
set rowcount 0 方法二
"重複記(jì)錄"有兩個意義上的重複記錄,一是完全重複的記錄(lù),也即所有字段均重複的記錄,二(èr)是部分關(guān)鍵字段重複的記錄,比如Name字段重複(fù),而(ér)其他字段(duàn)不一定重複或都重複(fù)可以忽略。
1、對於第一種重複(fù),比較容易解決,使用
select distinct * from tableName
就可以得到無重複記錄的結果集。
如果該表需要刪除重複的記錄(重複記(jì)錄保留1條),可以按以下方(fāng)法刪除
select distinct * into #Tmp from tableName
drop table tableName
select * into tableName from #Tmp
drop table #Tmp
發生這種重複的原因是表(biǎo)設計不(bú)周(zhōu)產生的,增加唯一索引列即可(kě)解決(jué)。
2、這類(lèi)重複(fù)問題通常要求保留重複記錄中(zhōng)的第一條記錄,操作方法如下
假設有重複的(de)字段為(wéi) Name,Address,要求得到這兩個字(zì)段唯一的結(jié)果集(jí)
select identity(int,1,1) as autoID, * into #Tmp from tableName
select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
select * from #Tmp where autoID in(select autoID from #tmp2)
最後一個select即得到了 Name,Address不重複的結果集(jí)(但多了一個autoID字段,實際寫時可以寫在select子句(jù)中省去此(cǐ)列)
(四)
查詢重複
select * from tablename where id in (
select id from tablename
group by id
having count(id) > 1
)
關鍵詞:Oracle,數據庫,SQL語句
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